3x^2-5x+(2k-4)=0

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Solution for 3x^2-5x+(2k-4)=0 equation:


Simplifying
3x2 + -5x + (2k + -4) = 0

Reorder the terms:
3x2 + -5x + (-4 + 2k) = 0

Remove parenthesis around (-4 + 2k)
3x2 + -5x + -4 + 2k = 0

Reorder the terms:
-4 + 2k + -5x + 3x2 = 0

Solving
-4 + 2k + -5x + 3x2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 2k + -5x + 4 + 3x2 = 0 + 4

Reorder the terms:
-4 + 4 + 2k + -5x + 3x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 2k + -5x + 3x2 = 0 + 4
2k + -5x + 3x2 = 0 + 4

Combine like terms: 0 + 4 = 4
2k + -5x + 3x2 = 4

Add '5x' to each side of the equation.
2k + -5x + 5x + 3x2 = 4 + 5x

Combine like terms: -5x + 5x = 0
2k + 0 + 3x2 = 4 + 5x
2k + 3x2 = 4 + 5x

Add '-3x2' to each side of the equation.
2k + 3x2 + -3x2 = 4 + 5x + -3x2

Combine like terms: 3x2 + -3x2 = 0
2k + 0 = 4 + 5x + -3x2
2k = 4 + 5x + -3x2

Divide each side by '2'.
k = 2 + 2.5x + -1.5x2

Simplifying
k = 2 + 2.5x + -1.5x2

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